Integrand size = 25, antiderivative size = 322 \[ \int \frac {1}{(d \csc (a+b x))^{3/2} \sqrt {c \sec (a+b x)}} \, dx=-\frac {c}{2 b d \sqrt {d \csc (a+b x)} (c \sec (a+b x))^{3/2}}-\frac {\arctan \left (1-\sqrt {2} \sqrt {\tan (a+b x)}\right ) \sqrt {d \csc (a+b x)} \sqrt {\tan (a+b x)}}{4 \sqrt {2} b d^2 \sqrt {c \sec (a+b x)}}+\frac {\arctan \left (1+\sqrt {2} \sqrt {\tan (a+b x)}\right ) \sqrt {d \csc (a+b x)} \sqrt {\tan (a+b x)}}{4 \sqrt {2} b d^2 \sqrt {c \sec (a+b x)}}-\frac {\sqrt {d \csc (a+b x)} \log \left (1-\sqrt {2} \sqrt {\tan (a+b x)}+\tan (a+b x)\right ) \sqrt {\tan (a+b x)}}{8 \sqrt {2} b d^2 \sqrt {c \sec (a+b x)}}+\frac {\sqrt {d \csc (a+b x)} \log \left (1+\sqrt {2} \sqrt {\tan (a+b x)}+\tan (a+b x)\right ) \sqrt {\tan (a+b x)}}{8 \sqrt {2} b d^2 \sqrt {c \sec (a+b x)}} \]
-1/2*c/b/d/(c*sec(b*x+a))^(3/2)/(d*csc(b*x+a))^(1/2)+1/8*arctan(-1+2^(1/2) *tan(b*x+a)^(1/2))*(d*csc(b*x+a))^(1/2)*tan(b*x+a)^(1/2)/b/d^2*2^(1/2)/(c* sec(b*x+a))^(1/2)+1/8*arctan(1+2^(1/2)*tan(b*x+a)^(1/2))*(d*csc(b*x+a))^(1 /2)*tan(b*x+a)^(1/2)/b/d^2*2^(1/2)/(c*sec(b*x+a))^(1/2)-1/16*ln(1-2^(1/2)* tan(b*x+a)^(1/2)+tan(b*x+a))*(d*csc(b*x+a))^(1/2)*tan(b*x+a)^(1/2)/b/d^2*2 ^(1/2)/(c*sec(b*x+a))^(1/2)+1/16*ln(1+2^(1/2)*tan(b*x+a)^(1/2)+tan(b*x+a)) *(d*csc(b*x+a))^(1/2)*tan(b*x+a)^(1/2)/b/d^2*2^(1/2)/(c*sec(b*x+a))^(1/2)
Time = 2.67 (sec) , antiderivative size = 156, normalized size of antiderivative = 0.48 \[ \int \frac {1}{(d \csc (a+b x))^{3/2} \sqrt {c \sec (a+b x)}} \, dx=-\frac {\left (4 \cos ^2(a+b x)+\sqrt {2} \arctan \left (\frac {-1+\sqrt {\cot ^2(a+b x)}}{\sqrt {2} \sqrt [4]{\cot ^2(a+b x)}}\right ) \sqrt [4]{\cot ^2(a+b x)}-\sqrt {2} \text {arctanh}\left (\frac {\sqrt {2} \sqrt [4]{\cot ^2(a+b x)}}{1+\sqrt {\cot ^2(a+b x)}}\right ) \sqrt [4]{\cot ^2(a+b x)}\right ) \sqrt {d \csc (a+b x)} \tan (a+b x)}{8 b d^2 \sqrt {c \sec (a+b x)}} \]
-1/8*((4*Cos[a + b*x]^2 + Sqrt[2]*ArcTan[(-1 + Sqrt[Cot[a + b*x]^2])/(Sqrt [2]*(Cot[a + b*x]^2)^(1/4))]*(Cot[a + b*x]^2)^(1/4) - Sqrt[2]*ArcTanh[(Sqr t[2]*(Cot[a + b*x]^2)^(1/4))/(1 + Sqrt[Cot[a + b*x]^2])]*(Cot[a + b*x]^2)^ (1/4))*Sqrt[d*Csc[a + b*x]]*Tan[a + b*x])/(b*d^2*Sqrt[c*Sec[a + b*x]])
Time = 0.60 (sec) , antiderivative size = 212, normalized size of antiderivative = 0.66, number of steps used = 16, number of rules used = 15, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.600, Rules used = {3042, 3107, 3042, 3109, 3042, 3957, 266, 755, 1476, 1082, 217, 1479, 25, 27, 1103}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
| \(\displaystyle \int \frac {1}{\sqrt {c \sec (a+b x)} (d \csc (a+b x))^{3/2}} \, dx\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle \int \frac {1}{\sqrt {c \sec (a+b x)} (d \csc (a+b x))^{3/2}}dx\) |
| \(\Big \downarrow \) 3107 |
| \(\displaystyle \frac {\int \frac {\sqrt {d \csc (a+b x)}}{\sqrt {c \sec (a+b x)}}dx}{4 d^2}-\frac {c}{2 b d (c \sec (a+b x))^{3/2} \sqrt {d \csc (a+b x)}}\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle \frac {\int \frac {\sqrt {d \csc (a+b x)}}{\sqrt {c \sec (a+b x)}}dx}{4 d^2}-\frac {c}{2 b d (c \sec (a+b x))^{3/2} \sqrt {d \csc (a+b x)}}\) |
| \(\Big \downarrow \) 3109 |
| \(\displaystyle \frac {\sqrt {\tan (a+b x)} \sqrt {d \csc (a+b x)} \int \frac {1}{\sqrt {\tan (a+b x)}}dx}{4 d^2 \sqrt {c \sec (a+b x)}}-\frac {c}{2 b d (c \sec (a+b x))^{3/2} \sqrt {d \csc (a+b x)}}\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle \frac {\sqrt {\tan (a+b x)} \sqrt {d \csc (a+b x)} \int \frac {1}{\sqrt {\tan (a+b x)}}dx}{4 d^2 \sqrt {c \sec (a+b x)}}-\frac {c}{2 b d (c \sec (a+b x))^{3/2} \sqrt {d \csc (a+b x)}}\) |
| \(\Big \downarrow \) 3957 |
| \(\displaystyle \frac {\sqrt {\tan (a+b x)} \sqrt {d \csc (a+b x)} \int \frac {1}{\sqrt {\tan (a+b x)} \left (\tan ^2(a+b x)+1\right )}d\tan (a+b x)}{4 b d^2 \sqrt {c \sec (a+b x)}}-\frac {c}{2 b d (c \sec (a+b x))^{3/2} \sqrt {d \csc (a+b x)}}\) |
| \(\Big \downarrow \) 266 |
| \(\displaystyle \frac {\sqrt {\tan (a+b x)} \sqrt {d \csc (a+b x)} \int \frac {1}{\tan ^2(a+b x)+1}d\sqrt {\tan (a+b x)}}{2 b d^2 \sqrt {c \sec (a+b x)}}-\frac {c}{2 b d (c \sec (a+b x))^{3/2} \sqrt {d \csc (a+b x)}}\) |
| \(\Big \downarrow \) 755 |
| \(\displaystyle \frac {\sqrt {\tan (a+b x)} \sqrt {d \csc (a+b x)} \left (\frac {1}{2} \int \frac {1-\tan (a+b x)}{\tan ^2(a+b x)+1}d\sqrt {\tan (a+b x)}+\frac {1}{2} \int \frac {\tan (a+b x)+1}{\tan ^2(a+b x)+1}d\sqrt {\tan (a+b x)}\right )}{2 b d^2 \sqrt {c \sec (a+b x)}}-\frac {c}{2 b d (c \sec (a+b x))^{3/2} \sqrt {d \csc (a+b x)}}\) |
| \(\Big \downarrow \) 1476 |
| \(\displaystyle \frac {\sqrt {\tan (a+b x)} \sqrt {d \csc (a+b x)} \left (\frac {1}{2} \int \frac {1-\tan (a+b x)}{\tan ^2(a+b x)+1}d\sqrt {\tan (a+b x)}+\frac {1}{2} \left (\frac {1}{2} \int \frac {1}{\tan (a+b x)-\sqrt {2} \sqrt {\tan (a+b x)}+1}d\sqrt {\tan (a+b x)}+\frac {1}{2} \int \frac {1}{\tan (a+b x)+\sqrt {2} \sqrt {\tan (a+b x)}+1}d\sqrt {\tan (a+b x)}\right )\right )}{2 b d^2 \sqrt {c \sec (a+b x)}}-\frac {c}{2 b d (c \sec (a+b x))^{3/2} \sqrt {d \csc (a+b x)}}\) |
| \(\Big \downarrow \) 1082 |
| \(\displaystyle \frac {\sqrt {\tan (a+b x)} \sqrt {d \csc (a+b x)} \left (\frac {1}{2} \int \frac {1-\tan (a+b x)}{\tan ^2(a+b x)+1}d\sqrt {\tan (a+b x)}+\frac {1}{2} \left (\frac {\int \frac {1}{-\tan (a+b x)-1}d\left (1-\sqrt {2} \sqrt {\tan (a+b x)}\right )}{\sqrt {2}}-\frac {\int \frac {1}{-\tan (a+b x)-1}d\left (\sqrt {2} \sqrt {\tan (a+b x)}+1\right )}{\sqrt {2}}\right )\right )}{2 b d^2 \sqrt {c \sec (a+b x)}}-\frac {c}{2 b d (c \sec (a+b x))^{3/2} \sqrt {d \csc (a+b x)}}\) |
| \(\Big \downarrow \) 217 |
| \(\displaystyle \frac {\sqrt {\tan (a+b x)} \sqrt {d \csc (a+b x)} \left (\frac {1}{2} \int \frac {1-\tan (a+b x)}{\tan ^2(a+b x)+1}d\sqrt {\tan (a+b x)}+\frac {1}{2} \left (\frac {\arctan \left (\sqrt {2} \sqrt {\tan (a+b x)}+1\right )}{\sqrt {2}}-\frac {\arctan \left (1-\sqrt {2} \sqrt {\tan (a+b x)}\right )}{\sqrt {2}}\right )\right )}{2 b d^2 \sqrt {c \sec (a+b x)}}-\frac {c}{2 b d (c \sec (a+b x))^{3/2} \sqrt {d \csc (a+b x)}}\) |
| \(\Big \downarrow \) 1479 |
| \(\displaystyle \frac {\sqrt {\tan (a+b x)} \sqrt {d \csc (a+b x)} \left (\frac {1}{2} \left (-\frac {\int -\frac {\sqrt {2}-2 \sqrt {\tan (a+b x)}}{\tan (a+b x)-\sqrt {2} \sqrt {\tan (a+b x)}+1}d\sqrt {\tan (a+b x)}}{2 \sqrt {2}}-\frac {\int -\frac {\sqrt {2} \left (\sqrt {2} \sqrt {\tan (a+b x)}+1\right )}{\tan (a+b x)+\sqrt {2} \sqrt {\tan (a+b x)}+1}d\sqrt {\tan (a+b x)}}{2 \sqrt {2}}\right )+\frac {1}{2} \left (\frac {\arctan \left (\sqrt {2} \sqrt {\tan (a+b x)}+1\right )}{\sqrt {2}}-\frac {\arctan \left (1-\sqrt {2} \sqrt {\tan (a+b x)}\right )}{\sqrt {2}}\right )\right )}{2 b d^2 \sqrt {c \sec (a+b x)}}-\frac {c}{2 b d (c \sec (a+b x))^{3/2} \sqrt {d \csc (a+b x)}}\) |
| \(\Big \downarrow \) 25 |
| \(\displaystyle \frac {\sqrt {\tan (a+b x)} \sqrt {d \csc (a+b x)} \left (\frac {1}{2} \left (\frac {\int \frac {\sqrt {2}-2 \sqrt {\tan (a+b x)}}{\tan (a+b x)-\sqrt {2} \sqrt {\tan (a+b x)}+1}d\sqrt {\tan (a+b x)}}{2 \sqrt {2}}+\frac {\int \frac {\sqrt {2} \left (\sqrt {2} \sqrt {\tan (a+b x)}+1\right )}{\tan (a+b x)+\sqrt {2} \sqrt {\tan (a+b x)}+1}d\sqrt {\tan (a+b x)}}{2 \sqrt {2}}\right )+\frac {1}{2} \left (\frac {\arctan \left (\sqrt {2} \sqrt {\tan (a+b x)}+1\right )}{\sqrt {2}}-\frac {\arctan \left (1-\sqrt {2} \sqrt {\tan (a+b x)}\right )}{\sqrt {2}}\right )\right )}{2 b d^2 \sqrt {c \sec (a+b x)}}-\frac {c}{2 b d (c \sec (a+b x))^{3/2} \sqrt {d \csc (a+b x)}}\) |
| \(\Big \downarrow \) 27 |
| \(\displaystyle \frac {\sqrt {\tan (a+b x)} \sqrt {d \csc (a+b x)} \left (\frac {1}{2} \left (\frac {\int \frac {\sqrt {2}-2 \sqrt {\tan (a+b x)}}{\tan (a+b x)-\sqrt {2} \sqrt {\tan (a+b x)}+1}d\sqrt {\tan (a+b x)}}{2 \sqrt {2}}+\frac {1}{2} \int \frac {\sqrt {2} \sqrt {\tan (a+b x)}+1}{\tan (a+b x)+\sqrt {2} \sqrt {\tan (a+b x)}+1}d\sqrt {\tan (a+b x)}\right )+\frac {1}{2} \left (\frac {\arctan \left (\sqrt {2} \sqrt {\tan (a+b x)}+1\right )}{\sqrt {2}}-\frac {\arctan \left (1-\sqrt {2} \sqrt {\tan (a+b x)}\right )}{\sqrt {2}}\right )\right )}{2 b d^2 \sqrt {c \sec (a+b x)}}-\frac {c}{2 b d (c \sec (a+b x))^{3/2} \sqrt {d \csc (a+b x)}}\) |
| \(\Big \downarrow \) 1103 |
| \(\displaystyle \frac {\sqrt {\tan (a+b x)} \sqrt {d \csc (a+b x)} \left (\frac {1}{2} \left (\frac {\arctan \left (\sqrt {2} \sqrt {\tan (a+b x)}+1\right )}{\sqrt {2}}-\frac {\arctan \left (1-\sqrt {2} \sqrt {\tan (a+b x)}\right )}{\sqrt {2}}\right )+\frac {1}{2} \left (\frac {\log \left (\tan (a+b x)+\sqrt {2} \sqrt {\tan (a+b x)}+1\right )}{2 \sqrt {2}}-\frac {\log \left (\tan (a+b x)-\sqrt {2} \sqrt {\tan (a+b x)}+1\right )}{2 \sqrt {2}}\right )\right )}{2 b d^2 \sqrt {c \sec (a+b x)}}-\frac {c}{2 b d (c \sec (a+b x))^{3/2} \sqrt {d \csc (a+b x)}}\) |
-1/2*c/(b*d*Sqrt[d*Csc[a + b*x]]*(c*Sec[a + b*x])^(3/2)) + (Sqrt[d*Csc[a + b*x]]*((-(ArcTan[1 - Sqrt[2]*Sqrt[Tan[a + b*x]]]/Sqrt[2]) + ArcTan[1 + Sq rt[2]*Sqrt[Tan[a + b*x]]]/Sqrt[2])/2 + (-1/2*Log[1 - Sqrt[2]*Sqrt[Tan[a + b*x]] + Tan[a + b*x]]/Sqrt[2] + Log[1 + Sqrt[2]*Sqrt[Tan[a + b*x]] + Tan[a + b*x]]/(2*Sqrt[2]))/2)*Sqrt[Tan[a + b*x]])/(2*b*d^2*Sqrt[c*Sec[a + b*x]] )
3.3.60.3.1 Defintions of rubi rules used
Int[(a_)*(Fx_), x_Symbol] :> Simp[a Int[Fx, x], x] /; FreeQ[a, x] && !Ma tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(-(Rt[-a, 2]*Rt[-b, 2])^( -1))*ArcTan[Rt[-b, 2]*(x/Rt[-a, 2])], x] /; FreeQ[{a, b}, x] && PosQ[a/b] & & (LtQ[a, 0] || LtQ[b, 0])
Int[((c_.)*(x_))^(m_)*((a_) + (b_.)*(x_)^2)^(p_), x_Symbol] :> With[{k = De nominator[m]}, Simp[k/c Subst[Int[x^(k*(m + 1) - 1)*(a + b*(x^(2*k)/c^2)) ^p, x], x, (c*x)^(1/k)], x]] /; FreeQ[{a, b, c, p}, x] && FractionQ[m] && I ntBinomialQ[a, b, c, 2, m, p, x]
Int[((a_) + (b_.)*(x_)^4)^(-1), x_Symbol] :> With[{r = Numerator[Rt[a/b, 2] ], s = Denominator[Rt[a/b, 2]]}, Simp[1/(2*r) Int[(r - s*x^2)/(a + b*x^4) , x], x] + Simp[1/(2*r) Int[(r + s*x^2)/(a + b*x^4), x], x]] /; FreeQ[{a, b}, x] && (GtQ[a/b, 0] || (PosQ[a/b] && AtomQ[SplitProduct[SumBaseQ, a]] & & AtomQ[SplitProduct[SumBaseQ, b]]))
Int[((a_) + (b_.)*(x_) + (c_.)*(x_)^2)^(-1), x_Symbol] :> With[{q = 1 - 4*S implify[a*(c/b^2)]}, Simp[-2/b Subst[Int[1/(q - x^2), x], x, 1 + 2*c*(x/b )], x] /; RationalQ[q] && (EqQ[q^2, 1] || !RationalQ[b^2 - 4*a*c])] /; Fre eQ[{a, b, c}, x]
Int[((d_) + (e_.)*(x_))/((a_.) + (b_.)*(x_) + (c_.)*(x_)^2), x_Symbol] :> S imp[d*(Log[RemoveContent[a + b*x + c*x^2, x]]/b), x] /; FreeQ[{a, b, c, d, e}, x] && EqQ[2*c*d - b*e, 0]
Int[((d_) + (e_.)*(x_)^2)/((a_) + (c_.)*(x_)^4), x_Symbol] :> With[{q = Rt[ 2*(d/e), 2]}, Simp[e/(2*c) Int[1/Simp[d/e + q*x + x^2, x], x], x] + Simp[ e/(2*c) Int[1/Simp[d/e - q*x + x^2, x], x], x]] /; FreeQ[{a, c, d, e}, x] && EqQ[c*d^2 - a*e^2, 0] && PosQ[d*e]
Int[((d_) + (e_.)*(x_)^2)/((a_) + (c_.)*(x_)^4), x_Symbol] :> With[{q = Rt[ -2*(d/e), 2]}, Simp[e/(2*c*q) Int[(q - 2*x)/Simp[d/e + q*x - x^2, x], x], x] + Simp[e/(2*c*q) Int[(q + 2*x)/Simp[d/e - q*x - x^2, x], x], x]] /; F reeQ[{a, c, d, e}, x] && EqQ[c*d^2 - a*e^2, 0] && NegQ[d*e]
Int[(csc[(e_.) + (f_.)*(x_)]*(a_.))^(m_)*((b_.)*sec[(e_.) + (f_.)*(x_)])^(n _.), x_Symbol] :> Simp[b*(a*Csc[e + f*x])^(m + 1)*((b*Sec[e + f*x])^(n - 1) /(a*f*(m + n))), x] + Simp[(m + 1)/(a^2*(m + n)) Int[(a*Csc[e + f*x])^(m + 2)*(b*Sec[e + f*x])^n, x], x] /; FreeQ[{a, b, e, f, n}, x] && LtQ[m, -1] && NeQ[m + n, 0] && IntegersQ[2*m, 2*n]
Int[(csc[(e_.) + (f_.)*(x_)]*(a_.))^(m_)*((b_.)*sec[(e_.) + (f_.)*(x_)])^(n _), x_Symbol] :> Simp[(a*Csc[e + f*x])^m*((b*Sec[e + f*x])^n/Tan[e + f*x]^n ) Int[Tan[e + f*x]^n, x], x] /; FreeQ[{a, b, e, f, m, n}, x] && !Integer Q[n] && EqQ[m + n, 0]
Int[((b_.)*tan[(c_.) + (d_.)*(x_)])^(n_), x_Symbol] :> Simp[b/d Subst[Int [x^n/(b^2 + x^2), x], x, b*Tan[c + d*x]], x] /; FreeQ[{b, c, d, n}, x] && !IntegerQ[n]
Time = 1.73 (sec) , antiderivative size = 434, normalized size of antiderivative = 1.35
| method | result | size |
| default | \(-\frac {\sqrt {2}\, \left (4 \sqrt {-\frac {\cos \left (b x +a \right ) \sin \left (b x +a \right )}{\left (\cos \left (b x +a \right )+1\right )^{2}}}\, \sqrt {2}\, \cos \left (b x +a \right )^{2}+4 \cos \left (b x +a \right ) \sqrt {2}\, \sqrt {-\frac {\cos \left (b x +a \right ) \sin \left (b x +a \right )}{\left (\cos \left (b x +a \right )+1\right )^{2}}}-2 \arctan \left (\frac {-\sin \left (b x +a \right ) \sqrt {2}\, \sqrt {-\frac {\cos \left (b x +a \right ) \sin \left (b x +a \right )}{\left (\cos \left (b x +a \right )+1\right )^{2}}}+\cos \left (b x +a \right )-1}{\cos \left (b x +a \right )-1}\right )+\ln \left (2 \sqrt {2}\, \sqrt {-\frac {\cos \left (b x +a \right ) \sin \left (b x +a \right )}{\left (\cos \left (b x +a \right )+1\right )^{2}}}\, \cot \left (b x +a \right )+2 \sqrt {2}\, \sqrt {-\frac {\cos \left (b x +a \right ) \sin \left (b x +a \right )}{\left (\cos \left (b x +a \right )+1\right )^{2}}}\, \csc \left (b x +a \right )-2 \cot \left (b x +a \right )+2\right )-\ln \left (-2 \sqrt {2}\, \sqrt {-\frac {\cos \left (b x +a \right ) \sin \left (b x +a \right )}{\left (\cos \left (b x +a \right )+1\right )^{2}}}\, \cot \left (b x +a \right )-2 \sqrt {2}\, \sqrt {-\frac {\cos \left (b x +a \right ) \sin \left (b x +a \right )}{\left (\cos \left (b x +a \right )+1\right )^{2}}}\, \csc \left (b x +a \right )-2 \cot \left (b x +a \right )+2\right )+2 \arctan \left (\frac {\sin \left (b x +a \right ) \sqrt {2}\, \sqrt {-\frac {\cos \left (b x +a \right ) \sin \left (b x +a \right )}{\left (\cos \left (b x +a \right )+1\right )^{2}}}+\cos \left (b x +a \right )-1}{\cos \left (b x +a \right )-1}\right )\right )}{16 b \left (\cos \left (b x +a \right )+1\right ) \sqrt {-\frac {\cos \left (b x +a \right ) \sin \left (b x +a \right )}{\left (\cos \left (b x +a \right )+1\right )^{2}}}\, \sqrt {d \csc \left (b x +a \right )}\, \sqrt {c \sec \left (b x +a \right )}\, d}\) | \(434\) |
-1/16/b*2^(1/2)*(4*(-cos(b*x+a)*sin(b*x+a)/(cos(b*x+a)+1)^2)^(1/2)*2^(1/2) *cos(b*x+a)^2+4*cos(b*x+a)*2^(1/2)*(-cos(b*x+a)*sin(b*x+a)/(cos(b*x+a)+1)^ 2)^(1/2)-2*arctan((-sin(b*x+a)*2^(1/2)*(-cos(b*x+a)*sin(b*x+a)/(cos(b*x+a) +1)^2)^(1/2)+cos(b*x+a)-1)/(cos(b*x+a)-1))+ln(2*2^(1/2)*(-cos(b*x+a)*sin(b *x+a)/(cos(b*x+a)+1)^2)^(1/2)*cot(b*x+a)+2*2^(1/2)*(-cos(b*x+a)*sin(b*x+a) /(cos(b*x+a)+1)^2)^(1/2)*csc(b*x+a)-2*cot(b*x+a)+2)-ln(-2*2^(1/2)*(-cos(b* x+a)*sin(b*x+a)/(cos(b*x+a)+1)^2)^(1/2)*cot(b*x+a)-2*2^(1/2)*(-cos(b*x+a)* sin(b*x+a)/(cos(b*x+a)+1)^2)^(1/2)*csc(b*x+a)-2*cot(b*x+a)+2)+2*arctan((si n(b*x+a)*2^(1/2)*(-cos(b*x+a)*sin(b*x+a)/(cos(b*x+a)+1)^2)^(1/2)+cos(b*x+a )-1)/(cos(b*x+a)-1)))/(cos(b*x+a)+1)/(-cos(b*x+a)*sin(b*x+a)/(cos(b*x+a)+1 )^2)^(1/2)/(d*csc(b*x+a))^(1/2)/(c*sec(b*x+a))^(1/2)/d
Result contains complex when optimal does not.
Time = 0.67 (sec) , antiderivative size = 1268, normalized size of antiderivative = 3.94 \[ \int \frac {1}{(d \csc (a+b x))^{3/2} \sqrt {c \sec (a+b x)}} \, dx=\text {Too large to display} \]
-1/32*(b*c*d^2*(-1/(b^4*c^2*d^6))^(1/4)*log(2*(b^3*c*d^4*(-1/(b^4*c^2*d^6) )^(3/4)*cos(b*x + a)^2*sin(b*x + a) + (b*d*cos(b*x + a)^3 - b*d*cos(b*x + a))*(-1/(b^4*c^2*d^6))^(1/4))*sqrt(c/cos(b*x + a))*sqrt(d/sin(b*x + a)) + 1) - b*c*d^2*(-1/(b^4*c^2*d^6))^(1/4)*log(-2*(b^3*c*d^4*(-1/(b^4*c^2*d^6)) ^(3/4)*cos(b*x + a)^2*sin(b*x + a) + (b*d*cos(b*x + a)^3 - b*d*cos(b*x + a ))*(-1/(b^4*c^2*d^6))^(1/4))*sqrt(c/cos(b*x + a))*sqrt(d/sin(b*x + a)) + 1 ) + I*b*c*d^2*(-1/(b^4*c^2*d^6))^(1/4)*log(-2*(I*b^3*c*d^4*(-1/(b^4*c^2*d^ 6))^(3/4)*cos(b*x + a)^2*sin(b*x + a) + (-I*b*d*cos(b*x + a)^3 + I*b*d*cos (b*x + a))*(-1/(b^4*c^2*d^6))^(1/4))*sqrt(c/cos(b*x + a))*sqrt(d/sin(b*x + a)) + 1) - I*b*c*d^2*(-1/(b^4*c^2*d^6))^(1/4)*log(-2*(-I*b^3*c*d^4*(-1/(b ^4*c^2*d^6))^(3/4)*cos(b*x + a)^2*sin(b*x + a) + (I*b*d*cos(b*x + a)^3 - I *b*d*cos(b*x + a))*(-1/(b^4*c^2*d^6))^(1/4))*sqrt(c/cos(b*x + a))*sqrt(d/s in(b*x + a)) + 1) + b*c*d^2*(-1/(b^4*c^2*d^6))^(1/4)*log(1/2*(b*d*(-1/(b^4 *c^2*d^6))^(1/4)*cos(b*x + a)^2*sin(b*x + a) + (b^3*c*d^4*cos(b*x + a)^3 - b^3*c*d^4*cos(b*x + a))*(-1/(b^4*c^2*d^6))^(3/4))*sqrt(c/cos(b*x + a))*sq rt(d/sin(b*x + a)) - 1/2*cos(b*x + a)*sin(b*x + a) - 1/4*(2*b^2*c*d^3*cos( b*x + a)^2 - b^2*c*d^3)*sqrt(-1/(b^4*c^2*d^6))) - b*c*d^2*(-1/(b^4*c^2*d^6 ))^(1/4)*log(-1/2*(b*d*(-1/(b^4*c^2*d^6))^(1/4)*cos(b*x + a)^2*sin(b*x + a ) + (b^3*c*d^4*cos(b*x + a)^3 - b^3*c*d^4*cos(b*x + a))*(-1/(b^4*c^2*d^6)) ^(3/4))*sqrt(c/cos(b*x + a))*sqrt(d/sin(b*x + a)) - 1/2*cos(b*x + a)*si...
\[ \int \frac {1}{(d \csc (a+b x))^{3/2} \sqrt {c \sec (a+b x)}} \, dx=\int \frac {1}{\sqrt {c \sec {\left (a + b x \right )}} \left (d \csc {\left (a + b x \right )}\right )^{\frac {3}{2}}}\, dx \]
\[ \int \frac {1}{(d \csc (a+b x))^{3/2} \sqrt {c \sec (a+b x)}} \, dx=\int { \frac {1}{\left (d \csc \left (b x + a\right )\right )^{\frac {3}{2}} \sqrt {c \sec \left (b x + a\right )}} \,d x } \]
\[ \int \frac {1}{(d \csc (a+b x))^{3/2} \sqrt {c \sec (a+b x)}} \, dx=\int { \frac {1}{\left (d \csc \left (b x + a\right )\right )^{\frac {3}{2}} \sqrt {c \sec \left (b x + a\right )}} \,d x } \]
Timed out. \[ \int \frac {1}{(d \csc (a+b x))^{3/2} \sqrt {c \sec (a+b x)}} \, dx=\int \frac {1}{\sqrt {\frac {c}{\cos \left (a+b\,x\right )}}\,{\left (\frac {d}{\sin \left (a+b\,x\right )}\right )}^{3/2}} \,d x \]